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Question

# 50.0 mL of 0.10 M HCl is mixed with 50.0 mLof 0.10 M NaOH. The solution's temperature rises by 0.6oC. Calculate the enthalpy of neutralization per mole of HCl. Given : density and specific heat of solution is 1g mL−1 and 4.2 Jg−1 ∘C−1

A
50.4 kJ/mol
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B
54.4 kJ/mol
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C
57.7 kJ/mol
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D
63.2 kJ/mol
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Solution

## The correct option is A −50.4 kJ/molBalanced chemical reaction : HCl+NaOH→NaCl+H2O Milimoles = Molarity × Volume of solution in mL Milimoles of HCl = 0.1×50=5 mmol Milimoles of NaOH = 0.1×50=5 mmol Hence millimoles of acid neutralized = 5 mmol Specific heat capacity is 4.2 Jg−1 ∘C−1 Heat released (q)=ms△T=100×4.2×0.6=252 Enthalpy of neutralization per mole of HCl △H=−252J×10005=−50.4 kJ/mol

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