50 g of ice at 0-C is mixed with 50 g of water at 60-C- Final temperature of mixture will be-

Heat liberated when 50 g water at 60^∘C converts into water at 0^∘C. Q = ms Δθ = 50 × 1 × 60 = 3000 cal From this heat, mass of ice which can be melted is nb ...

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Standard XII

Chemistry

Stoichiometry

50 g of ice a...

Question

$50 g$ of ice at $0^{\circ} C$ is mixed with $50 g$ of water at $60^{\circ} C$ . Final temperature of mixture will be:

0^{\circ} C

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40^{\circ} C

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10^{\circ} C

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15^{\circ} C

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Solution

The correct option is A $0^{\circ} C$
Heat liberated when 50 g water at $60^{\circ} C$ converts into water at $0^{\circ} C$ .
$Q = m s Δ θ = 50 \times 1 \times 60 = 3000 cal$
From this heat, mass of ice which can be melted is
$m = \frac{Q}{L} = \frac{3000}{80} = 37.5 g$
i.e., whole ice is not melted, and temperature of mixture will be $0^{\circ} C$ .

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50 g of ice at 0∘C is mixed with 50 g of water at 60∘C. Final temperature of mixture will be:

The correct option is A 0∘CHeat liberated when 50 g water at 60∘C converts into water at 0∘C. Q=msΔθ=50×1×60=3000 cal From this heat, mass of ice which can be melted is m=QL=300080=37.5 g i.e., whole ice is not melted, and temperature of mixture will be 0∘C.

$50 g$ of ice at $0^{\circ} C$ is mixed with $50 g$ of water at $60^{\circ} C$ . Final temperature of mixture will be: