50 grams of 90% pure magnesium is made to react with excess HCl to form a gaseous product which was made to combine with chlorine gas completely to give a gaseous product. This, on dissolution in 50 ml water, produced a solution. The number of moles of HCl produced is:

3.75 mole

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1.875 mole

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7.50 mole

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none of these

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Solution

The correct option is A 3.75 mole
Reaction:
$M g + 2 H C l ⟶ M g C l_{2} + H_{2}$
Gaseous product is hydrogen
$H_{2} + C l_{2} ⟶ 2 H C l$
$A m o u n t o f p u r e M g i n 50 g s a m p l e = 45 g .$
$N u m b e r o f m o l e s = 1.875$
$1 m o l e M g ⟶ 1 m o l e H_{2}$
$1.875 m o l e M g ⟶ 1.875 H_{2}$
$1.875 m o l e s H_{2} ⟶ 2 \times 1.875 m o l e s$ of $H C l = 3.75 m o l e s$

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