Question

50 grams of ice at 0 degree c is mixed with 40gm of water at 60 degree c.then the ratio of ice and water at equilibrium is?(ans=2:7)(calorimetry)

Answer 1

Dear student,

as given:
amount of water is 40g at $60°c$.
when it will come to 0 degree then amount of energy will release = 40$\times 60\times 4.186J$ = 10046.4J
and we know that 333.55J energy is used to convert 1 g ice into water.
so amount of ice converted into water =
$$\begin{gathered} \frac{10046.4}{333.55}g=30g \\ sonowtotalamountofwater=40+30=70g \\ andamountofice=50-30=20g \\ soratiooficeandwaterwillbe2:7. \end{gathered}$$


Regards