$50 H z$ alternative current current of crest value $1 A$ flows through the primary of a transformer. If mutual inductance between the primary and secondary is $0.5 H$ , then crest voltage induced in the secondary is:

100 V

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150 V

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75 V

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50 V

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Solution

The correct option is A $100 V$
$d i = 2 - (1 - 1) = 2 A$

$d t = \frac{1}{100} sec.$

$E = M \frac{d i}{d t} = 0.5 \times \frac{2}{1 / 100}$

$= 100 V$

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50 Hz alternative current current of crest value 1A flows through the primary of a transformer. If mutual inductance between the primary and secondary is 0.5 H, then crest voltage induced in the secondary is:

The correct option is A 100 Vdi=2−(1−1)=2A dt=1100 sec. E=Mdidt=0.5×21/100 =100V

$50 H z$ alternative current current of crest value $1 A$ flows through the primary of a transformer. If mutual inductance between the primary and secondary is $0.5 H$ , then crest voltage induced in the secondary is:

The correct option is A $100 V$
$d i = 2 - (1 - 1) = 2 A$

$d t = \frac{1}{100} sec.$

$E = M \frac{d i}{d t} = 0.5 \times \frac{2}{1 / 100}$

$= 100 V$