A $50 H z$ alternating current of crest value $2.0$ . A flows through the primary of a transformer. If the mutual inductance between the primary and secondary is $0.25 H$ . The crest voltage induced in the secondary is

50 V

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100 V

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200 V

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300 V

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Solution

The correct option is B $100 V$
$e_{2} = m \frac{d i}{d t} = 0.25 \frac{(4 - (2 - 2))}{\frac{1}{100}}$
$e_{2} = 100 V$

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A 50 Hz alternating current of crest value 2.0. A flows through the primary of a transformer. If the mutual inductance between the primary and secondary is 0.25 H. The crest voltage induced in the secondary is

The correct option is B 100Ve2=mdidt=0.25(4−(2−2))1100e2=100V

A $50 H z$ alternating current of crest value $2.0$ . A flows through the primary of a transformer. If the mutual inductance between the primary and secondary is $0.25 H$ . The crest voltage induced in the secondary is

The correct option is B $100 V$
$e_{2} = m \frac{d i}{d t} = 0.25 \frac{(4 - (2 - 2))}{\frac{1}{100}}$
$e_{2} = 100 V$