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Byju's Answer
Standard XII
Chemistry
Rubber
50 mL of 0.5 ...
Question
50 mL of 0.5 M oxalic acid is needed to neutralize 25 mL of sodium hydroxide solution. The amount (in g) of NaOH in 50 mL of the given sodium hydroxide solution is :
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Q.
What volume of a 1 M solution of hydrochloric acid is needed to neutralize 80 ml of a 0.5 M sodium hydroxide solution?
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The amount of sodium hydroxide (in g) required to make 100 mL of its 0.5 M aqueous solution is
Q.
150
m
L
of
0.5
N
nitric acid solution at
25.35
o
C
was mixed with
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m
L
of
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12
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sulphuric acid is neutralised with
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