Question

50 ml of 1 M oxalic acid (mol. wt. =126) is shaken with 0.5 g of wood charcoal. The final concentration of solution after adsoption is 0.5 M. Calculate the amount of oxalic acid adsorbed per gram of charcoal.

Answer 1

Amount of oxalic acid present $=(-50$ $mL\times 1$ $M)\times {10}^{-3}$ $moles=5\times {10}^{-2}$ $moles$Number of moles absorbed $=(50\times 0.5)\times {10}^{-3}$ $moles=25\times {10}^{-3}=2.5\times {10}^{-2}$ $moles$Mass of oxalic acid absorbed $=(2.5\times {10}^{-2})\times 126=315\times {10}^{-2}=3.15$ $gm$

$3.15$ $gm$ oxalic acid $-0.5$ $g$ char coal.

$6.3$ $gm$ oxalic acid absorbed $-1$ $g$ charcoal.