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Question
50 mL of 1 Moxalic acid (molar mass =126) is shaken with 0.5 g of wood charcoal. The final concentration of the solution after adsorption is 0.5 M. Calculate the amount of oxalic acid adsorbed per gram of charcoal?
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Solution
The correct option is B 6.3
No. of moles of oxalic acid in 50 ml of 1 M = 50×10−3×1=5×10−2 moles
No. of moles adsorbed = 50×10−3(1−0.5)=2.5×10−2 moles
No. of moles of oxalic acid adsorbed = 2.5×10−2×126=315×10−2 moles =3.15 g
For 0.5 g, 3.15 g is adsorbed.
Therefore, for 1 g, 6.3 g is adsorbed.
Hence, option D is correct.
No. of moles of oxalic acid in 50 ml of 1 M = 50×10−3×1=5×10−2 moles
No. of moles adsorbed = 50×10−3(1−0.5)=2.5×10−2 moles
No. of moles of oxalic acid adsorbed = 2.5×10−2×126=315×10−2 moles =3.15 g
For 0.5 g, 3.15 g is adsorbed.
Therefore, for 1 g, 6.3 g is adsorbed.
Hence, option D is correct.
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