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Question

50 mL of a 0.1 M magnesium hydroxide solution on titrating with a solution of a mixture of 0.1 M solution of HCl and unknown H2SO4 gave a titre value of 50 mL. The molarity of the H2SO4 solution is:

A
0.05 M
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B
0.1 M
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C
0.25 M
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D
0.35 M
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Solution

The correct option is A 0.05 M
Let the molarity of H2SO4 solution be x M
So, n1×M1×V1=n2×M2×V2+n3×M3×V3
Where, n1=n-factor of Mg(OH)2=2
M1=molarity of Mg(OH)2=0.1 M
V1=volume of Mg(OH)2=50 mL
n2=n-factor of HCl=1
M2=molarity of HCl=0.1 M
V2=volume of HCl=150 mL
n3=n-factor of H2SO4=2
V3=volume of H2SO4=50 mL
M3=molarity of H2SO4=x M
2×0.1×50=1×0.1×50+2×x×50
x=0.05
The molarity of H2SO4 solution = 0.05 M

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