50 mL of a 0.1 M magnesium hydroxide solution on titrating with a solution of a mixture of 0.1 M solution of HCl and unknown H2SO4 gave a titre value of 50 mL. The molarity of the H2SO4 solution is:
A
0.05 M
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B
0.1 M
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C
0.25 M
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D
0.35 M
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Solution
The correct option is A 0.05 M Let the molarity of H2SO4 solution be x M So, n1×M1×V1=n2×M2×V2+n3×M3×V3 Where, n1=n-factor ofMg(OH)2=2 M1=molarity ofMg(OH)2=0.1 M V1=volume ofMg(OH)2=50 mL n2=n-factor ofHCl=1 M2=molarity ofHCl=0.1M V2=volume ofHCl=150 mL n3=n-factor ofH2SO4=2 V3=volume ofH2SO4=50 mL M3=molarity ofH2SO4=xM ∴2×0.1×50=1×0.1×50+2×x×50 ⇒x=0.05 ∴The molarity of H2SO4 solution = 0.05 M