50% of the X-ray coming from a Coolidge tube is able to pass through a 0.1 mm thick aluminium foil. If the potential difference between the target and the filament is increased, the fraction of the X-ray passing through the same foil will be:

No worries! We‘ve got your back. Try BYJU‘S free classes today!

< 50%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

> 50%

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B > 50%
The penetration depth for any wave is proportional to $\frac{1}{λ}$ , so if we increase the voltage the wavelength decrease, so now more X-ray pass through the foil so answer is >50%

Suggest Corrections

Similar questions

50% of the X-ray coming from a Coolidge tube is able to pass through a 0.1 mm thick aluminium foil. If the potential difference between the target and the filament is increased, the fraction of the X-ray passing through the same foil will be

Q. 50% of the X-ray coming from a Coolidge tube is able to pass through n 0.1 mm thick aluminium foil. The potential difference between the target and the filament is increased. The thickness of aluminium foil, which will allow 50% of the X-ray to pass through will be

Q. 50% of the X-ray coming from a Coolidge tube is able to pass through a 0.1 mm thick aluminium foil. The potential difference between the target and the filament is increased. The thickness of the aluminium foil that will allow 50% of the X-ray to pass through will be
(a) zero
(b) < 0.1 mm
(c) 0.1 mm
d) > 0.1 mm

50 %

of X-rays obtained from a Coolidge tube pass through

0.3

mm. thick aluminum foil. If the potential difference between the target and the cathode is increased, then the fraction of X-rays passing through the same foil will be :-

Q. 40% of the X-rays coming from a Coolidge tube can pass through 0.2 mm thick Al plate. The Anode voltage is increased. Now 40% of the X-rays will pass through Al foil of thickness.

Join BYJU'S Learning Program

50% of the X-ray coming from a Coolidge tube is able to pass through a 0.1 mm thick aluminium foil. If the potential difference between the target and the filament is increased, the fraction of the X-ray passing through the same foil will be:

The correct option is B > 50%The penetration depth for any wave is proportional to 1λ, so if we increase the voltage the wavelength decrease, so now more X-ray pass through the foil so answer is >50%

The correct option is B > 50%
The penetration depth for any wave is proportional to $\frac{1}{λ}$ , so if we increase the voltage the wavelength decrease, so now more X-ray pass through the foil so answer is >50%