Question

500 ml of 0.4 N HCl is mixed with 500 ml of 0.4 N NaOH. The heat energy released in this reaction is:

• A. 57.3 KJ
• B. 28.65 KJ
• C. 14.32 KJ
• D. 11.46 KJ

Answer 1

Answer: (D)

11.46 KJ

$500\times {10}^{-3}\times 0.4$ moles $=\frac{1}{2}\times \frac{4}{10}$
$=$ 0.2 moles
For one mole 57.3 K Joule heat energy
$\therefore$ For 0.2 mole $=$ 0.2 x 57.3 KJ
$\simeq$ 11.46 KJ

Option D is correct.