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Ideal Gas Equation

500 ml of a g...

Question

$500 m l$ of a gas A exerts a pressure $600 t o r r$ in a vessel. $400 m l$ of a gas B exerts a pressure $200 t o r r$ in another vessel. If the $2$ gases are mixed in a $3 L$ vessel then the total pressure of the gas is?

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Solution

$P_{A} V_{A} + P_{B} V_{B} = P_{T} V_{T} 500 \times 600 + 200 \times 400 = P_{T} \times 3000 P_{T} = 126.66 t o r r$

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