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Question

500 mL of a N5H2SO4 and 200 ml of N10NaOH are mixed. What will be the normality of H+ ions in the solution?

A
0.114 N
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B
0.328 N
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C
0.256 N
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D
0.780 N
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Solution

The correct option is A 0.114 N⇒Number of milliequivalents = Normality × volume in mL ⇒Number of milliequivalents of H2SO4 =15×500=100 milliequivalents ⇒Number of milliequivalents of NaOH =110×200=20 milliequivalents ⇒After mixing of the acid and the base, milliequivalents of H+ ions=100−20=80 milliequivalents ⇒Normality of H+ ions: milliequivalents total volume of the solution in mL=80700=0.114 N

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