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Standard XII

Chemistry

Introduction

50mL of 1 o...

Question

$50 m L$ of $1$ oxalic acid is shaken with $0.5 g$ wood charcoal. The final concentration of the solution after adsorption is $0.5 M$ . What is the amount of oxalic acid adsorbed per gram of carbon?

3.15 g

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3.45 g

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6.30 g

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10.08 g

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Solution

The correct option is A $3.15 g$

Total moles of oxalic acid= $50 m$ moles
Final concentration= $0.5 M$
Final number of moles= $0.5 \times 50 / 1000 \times 63 = 1.575 g$
Amount of oxalic acid adsorbed per gram= $1.575 \times 2$ = 3.15

Hence,option A is correct.

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Similar questions

50 m L

1 M

oxalic acid (molar mass

= 126

) is shaken with

0.5 g

of wood charcoal. The final concentration of the solution after adsorption is

0.5 M

. What is the amount of oxalic acid adsorbed per

g r a m

of carbon?

50 m L

1 M

oxalic acid (molar mass =126) is shaken with

0.5 g

of wood charcoal. The final concentration of the solution after adsorption is

0.5 M

. Calculate the amount of oxalic acid adsorbed per gram of charcoal?

50 ml of 1 M oxalic acid is shaken with 0.5 g wood charcoal. The final concentration of the solution after adsorption is 0.5 M. What is the amount of oxalic acid absorbed per gm of carbon?

50 ml of 1M oxalic acid is shaken with 0.5 g of wood charcoal. The final concentration of the solution after adsorption is 0.5 M. Calculate the amount of oxalic acid adsorbed per gram charcoal.

Q. 50 mL of 1 M oxalic acid (molar mass

= 126 {gmol}^{- 1}

) is shaken with 0.5 g of wood charcoal. The final concentration of the solution after adsorption is 0.5 M. The amount of oxalic acid (in grams) adsorbed per gram of the charcoal is:

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50mL of 1 oxalic acid is shaken with 0.5g wood charcoal. The final concentration of the solution after adsorption is 0.5 M. What is the amount of oxalic acid adsorbed per gram of carbon?

The correct option is A 3.15gTotal moles of oxalic acid=50m molesFinal concentration= 0.5MFinal number of moles= 0.5×50/1000×63=1.575g Amount of oxalic acid adsorbed per gram=1.575×2= 3.15Hence,option A is correct.

$50 m L$ of $1$ oxalic acid is shaken with $0.5 g$ wood charcoal. The final concentration of the solution after adsorption is $0.5 M$ . What is the amount of oxalic acid adsorbed per gram of carbon?

The correct option is A $3.15 g$

Total moles of oxalic acid= $50 m$ moles
Final concentration= $0.5 M$
Final number of moles= $0.5 \times 50 / 1000 \times 63 = 1.575 g$
Amount of oxalic acid adsorbed per gram= $1.575 \times 2$ = 3.15

Hence,option A is correct.