52.Explain electrochemical series really and difference bet reducing agent and oxidising agent. .oxidation potential and reduction potential and reduction and oxidation power

Open in App

Solution

Suggest Corrections

Similar questions

O_{3}

- 1

Potassium (at No. 19) and chlorine (at No. 17) form a compound. Explain the formation of the compound on the basis of :

(a) oxidation (b) reduction

Find out the process of oxidation , reduction. And oxidising agent ,reducing agent from the following.

1. MnO₂ + 4HCL ➡ MnCl₂ + 2H₂O + Cl₂

2.H₂S + SO₂➡ S+ H₂O

3.CuO + C ➡ Cu + CO

(i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode) (ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode) (iii)) EMF of cell = (Reductional potential of anode) + (Reduction potential of cathode) (i v)) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)

Join BYJU'S Learning Program