Question

$540$ g of ice at $0^{0}C$ is mixed with $540$ g of water at ${80}^{0}C$, the final temperature of the mixture in ${}^{0}C$ will be:

• A. 40
• B. 79.9
• C. 0
• D. 80

Answer 1

Answer: (C)

0

Let us assume that the complete ice melts and final temperature is T. Then, by principle of calorimetry,

$540\left(1\right)(80-T)=540\left(80\right)+540\left(0.5\right)(T-0)$

$80-T=80+0.5T$

$T=0^{0}C$

Hence, all the ice just melts and final temperature is $0^{0}C$.