540 g of ice at 0- C is mixed with 540 g of water at 80- C- The final temperature of the mixture is

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Specific Heat Capacity

540 g of ice ...

Question

540 g of ice at $0^{\circ} C$ is mixed with 540 g of water at $80^{\circ} C$ . The final temperature of the mixture is

$0^{\circ} C$

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$40^{\circ} C$

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$80^{\circ} C$

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Less than $0^{\circ} C$

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Solution

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Similar questions

540 g

0^{\circ}

540 g

80^{\circ} C

540

0^{0} C

540

80^{0} C

^{0} C

540 g of ice at $0^{\circ} C$ is mixed with 540 g of water at $80^{\circ} C$ . The final temperature of the mixture is

0^{\circ} C

1000^{\circ} C

1 g

100^{o} C

0^{o} C

= 540 c a l / g

= 80 c a l / g

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