56. [2/|x-3|]>1, find the values of x

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x^{3} = {(\frac{6}{5})}^{- 3} \times {(\frac{6}{5})}^{6} .

x

5^{x + 2} \times 5^{6} = 5^{10}

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(\frac{2}{5})^{3} \times (\frac{2}{5})^{6} = (\frac{2}{5})^{3 x}

(x + a) (x + b) = x^{2} + (a + b) x + a b

55 \times 56

\frac{1}{(x - 1) (x - 2)} + \frac{1}{(x - 2) (x - 3)} = \frac{2}{3}, x \neq 1, 2, 3

x

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