We know that, x×x=x2, z×z=z2 and 5×(−4)×3=−60.
∴5x×(−4yz)×3xz=−60x2yz2
5x×(−4yz)×3xz = ___
5x×(−4yz)×3xz = ___x2yz2
When 4yz+9zx−4y and −3xz+5x−2xy are added, we get 4yz+6xz−2xy−4y+5x.
Solve the following:Add 7xy+5yz−3zx,4yz+9zx−4y,−3xz+5x−2y