5x×(−4yz)×3xz = ___x2yz2
On multiplying x with x, its power is raised to 2; on multiplying z with z its power is also raised to 2.
On multiplying the numerical coefficients we get: 5×(−4)×3=−60
∴ 5x×(−4yz)×3xz=−60x2yz2
Solve the following:Add 7xy+5yz−3zx,4yz+9zx−4y,−3xz+5x−2y
When 4yz+9zx−4y and −3xz+5x−2xy are added, we get 4yz+6xz−2xy−4y+5x.
When 7xy + 5yz - 3zx, 4yz + 9zx - 4y and - 3xz + 5x - 2xy are added, we get