Question

$(-5y^2)\times (-11x{y}^2)\times \left(\frac{3}{10}{x}^2{y}^2\right)$ When $x=2,y=3$.

Answer 1

here, law of exponents says.

$\to$ When we have the same base for multiplying two numbers, we add the exponents. & for dividing two numbers, we subtract the exponent

So, $(-5y^2)x(-11x{y}^2)\times \left(\left(\frac{3}{10}\right)x^2{y}^2\right)$

$=(-5)\times (-11)\times \left(\frac{3}{10}\right)[y^2\times x\times y^2\times x^2\times y^2]$

$=\frac{33}{2}\times x^{1+2}\times y^{2+2+2}$

$=\frac{33}{2}{x}^3{y}^6$

here we have $x=2$ & $y=3$

So, $=\frac{33}{2}\left(2{)}^3\right(3{)}^6$

$=\frac{3\times 11}{2}\times \left(2{)}^3\right(3{)}^6$

$=(3{)}^{1+6}\times (11)\times (2{)}^{3-1}$

$=\left(2{)}^2\right(3{)}^7(11{)}^1$

or $=96228$

So, $(-5y^2)\times (-11x{y}^2)\times \left(\frac{3}{10}{x}^3{y}^2\right)=2^2{3}^7{11}^1$ or

$=96228$.