Subtract the sum of $5 y^{2} + y - 3$ and $y^{2} - 3 y + 7$ from $6 y^{2} + y - 2$ .

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Solution

Given,

$(6 y^{2} + y - 2) - [(5 y^{2} + y - 3) + (y^{2} - 3 y + 7)]$

$= (6 y^{2} + y - 2) - [6 y^{2} - 2 y + 4]$

$= 6 y^{2} + y - 2 - 6 y^{2} + 2 y - 4$

$= 3 y - 6$

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