Question

$6.02\times {10}^{20}$ molecules of urea are present in $100\text{mL}$ of its solution. The concentration of solution is:

• A. $0.001M$
• B. $0.1M$
• C. $0.02M$
• D. $0.01M$

Answer 1

The correct option is D $0.01M$

Moles of urea =$\frac{6.02\times {10}^{20}}{6.02\times {10}^{23}}=0.001$
Concentration of solution =$\frac{0.001}{100}\times 1000=0.01M$