Question

$6.02\times {10}^{22}$ molecules of urea are present in 100 mL of its solution. The concentration of solution is:

• A. 0.001 M
• B. 0.1 M
• C. 0.02 M
• D. 1 M

Answer 1

The correct option is D 1 M

Moles of urea=$\frac{6.02\times {10}^{22}}{6.022\times {10}^{23}}=0.1$

Hence Molarity=$\frac{0.1moles}{0.1L}=1M$

Hence, the correct option is $D$