Question

6. Identify the oxidising agent (oxidant) in the following reactions;

$$\begin{gathered} \circ \left(a\right)P{b}_3{O}_4+8HCl\to 3PbC{l}_2+C{l}_2+4H_{2}O \\ \circ \left(b\right)2Mg+O_2\to 2MgO \\ \circ \left(c\right)CuS{O}_4+Zn\to Cu+ZnS{O}_4 \\ \circ \left(d\right)V_2{O}_5+5Ca\to 2V+5CaO \\ \circ \left(e\right)3Fe+4H_{2}O\to F{e}_3{O}_4+4H_2 \\ \circ \left(f\right)CuO+H_2\to Cu+H_{2}O \end{gathered}$$

Answer 1

The solution is as follows:

Oxidising agent is the one that loses oxygen or gains hydrogen or both in a reaction.

1. Pb₃O₄ loses oxygen. So, it is oxidising agent.

2. O₂ loses one oxygen. It is oxidising agent.

3. CuSO_​4 loses oxygen, it is oxidising agent.

4. V₂O₅ is the oxidising agent.

5. H₂O is the oxidising agent.

6. CuO is the oxidising agent.