Question

$6$ moles of $A$ and $10$ moles of $B$ are mixed and allowed to react according to the equation:
$A+3B\to 2C$
How many moles of $C$ are present when there are $4$ moles of $A$ in the container?

Answer 1

$A+3B⟶2C$

$1$ mole $3$ mole $2mole$

So $1$ mole of $A$ reacts with $3$ moles of $B$ to form $2$ moles of $C$.

$6-4=2$ moles of $A$ will react

$\therefore$ $2$ moles of $A$ gives $4$ moles of $C$.

$\therefore$ $4$ moles of $C$ are present.