6- 10-3 mole K2Cr2O7 reacts completely with 9- 10-3 mole Xn- to give XO-3 and Cr3- The value of -n- is-

The correct option is A 1 Cr _ 2 O _ 7 ^ 2 +14 H ^ + +6 e ^ → 2 Cr ^ +3 + 7H _ 2 O X ^ n+ +3 H _ 2 O→ XO _ 3 ^ +6 H ^ + +(5 n) e ^ It is ...

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Byju's Answer

Standard XII

Chemistry

Electronic Configuration and Oxidation States

6× 10-3 mole ...

Question

$6 \times 10^{- 3}$ mole $K_{2} C r_{2} O_{7}$ reacts completely with $9 \times 10^{- 3}$ mole $X^{n +}$ to give $X O_{3}^{-}$ and $C r^{3 +}$ . The value of 'n' is?

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Solution

The correct option is A $1$
${C r}_{2} O_{7}^{2 -} + 14 H^{+} + 6 e^{-} \to 2 {C r}^{+ 3} + {7 H}_{2} O$
$X^{n +} + 3 H_{2} O \to {X O}_{3}^{-} + 6 H^{+} + (5 - n) e^{-}$
It is given that 2 moles of $K_{2} C r_{2} O_{7}$ reacts with 3 moles of $X^{n +}$ .So 2 $\times$ number of electrons gained in reduction half reaction=3 $\times$ number of electrons lost in oxidation half reaction
2 $\times$ 6=3 $\times$ (5-n)
$n = 1$

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Similar questions

6 \times 10^{- 3}

mole

K_{2} C r_{2} O_{7}

reacts completely with

9 \times 10^{- 3}

mole

X^{n +}

to give

X O_{3}^{-}

and

C r^{3 +}

. The value of

n

is:

6 \times 10^{- 3}

moles of

K_{2} C r_{2} O_{7}

react completely with

9 \times 10^{- 3}

moles of

X^{n +}

to give

X O_{3}^{-}

and

C r^{3 +}

. The value of

n

is :

6 \times 10^{- 3}

moles of

K_{2} C r_{2} O_{7}

reacts completely with

9 \times 10^{- 3}

moles of

X^{n +}

to give

X O_{3}^{-}

and

C r^{3 +}

. The value of n is:

3 X 10^{- 3}

mole

K_{2} C r_{2} O_{7}

reacts completely

4.5 X 10^{- 3}

mole

X^{n +}

to give

X O_{3}^{-}

and

C r^{3 +}

. The value of n is :

6 \times 10^{- 3}

moles of

K_{2} C r_{2} O_{7}

react completely with

9 \times 10^{- 3}

moles of

X^{n +}

to give

X O_{3}^{-}

and

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. The value of

n

is :

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6×10−3 mole K2Cr2O7 reacts completely with 9×10−3 mole Xn+ to give XO−3 and Cr3+. The value of 'n' is?

The correct option is A 1Cr2O2−7+14H++6e−→2Cr+3+7H2OXn++3H2O→XO−3+6H++(5−n)e−It is given that 2 moles of K2Cr2O7 reacts with 3 moles of Xn+.So 2×number of electrons gained in reduction half reaction=3× number of electrons lost in oxidation half reaction2×6=3×(5-n)n=1

$6 \times 10^{- 3}$ mole $K_{2} C r_{2} O_{7}$ reacts completely with $9 \times 10^{- 3}$ mole $X^{n +}$ to give $X O_{3}^{-}$ and $C r^{3 +}$ . The value of 'n' is?