Electronic Configuration and Oxidation States

Q. Nitrogen exist as a _____________ at room temperature.

1. Monoatomic gas
2. Diatomic gas
3. Triatomic gas
4. None of the options are corect

Q. Which of the following are appropriate oxidation states exhibited by the elements belonging to the group 15 family?

1. 5
2. 3
3. -3
4. All of these

Q. What is the change in oxidation number of nitrogen from $HN{O}_{2}toHN{O}_3$ in the following reaction? Ignore the other two products.
$3HN{O}_2\to HN{O}_3+2NO+H_{2}O$

1. 2
2. 3
3. 1
4. 4

Q. Which of the following statements is/are true?

1. Among the group 15 elements, Nitrogen has the lowest tendency for catenation
2. Among the group 15 elements, Phosphorus has the highest tendency for catenation
3. Both Nitrogen and Phosphorus do not exhibit catenation at all
4. Both Nitrogen and Phosphorus have very similar trends in terms of ability of catenate

Q.

Nitrogen has the electronic configuration $1s^2,2s^{2}2p_x^{1}2p_y^{1}2p_z^1$ and not $1s^2,2s^{2}2p_x^{2}2p_y^{1}2p_z^0$ which is determined by

1. Pauli's exclusion principle

2. Hund's rule

3. Uncertainty principle

4. Aufbau's principle

Q. Which one of the following oxides exhibits paramagnetic behaviour?

1. $S{O}_2$
2. $C{O}_2$
3. $Cl{O}_2$
4. $Si{O}_2$

Q. The element $Z=114$ has been discovered recently. It will belong to which of the following family groups and electronic configuration?

1. Halogen family, $\left[Rn\right]5f^{1}46d^{1}07s^{2}7p^5$
2. Carbon family, $\left[Rn\right]5f^{1}46d^{1}07s^{2}7p^2$
3. Oxygen family, $\left[Rn\right]5f^{1}46d^{1}07s^{2}7p^4$
4. Nitrogen family, $\left[Rn\right]5f^{1}46d^{1}07s^{2}7p^6$

Q. Which of the following species has the electronic configuration $\left[Ar\right]3d^5$?

1. $F{e}^{3+}$
2. $Mn$
3. $V$
4. $Cr$

Q. If the electrons in chromium $\left(Cr\right)$ have $m_l=+1$ and $m_s=-\frac{1}{2}$, then:

1. The minimum number of such electrons is 3
2. The minimum number of such electrons is 2
3. The maximum number of such electrons is 3
4. The maximum number of such electrons is 4

Q. The oxidation state of Oxygen in $K{O}_2$ is .

1. +$\frac{1}{2}$
2. -$\frac{1}{2}$
3. -2