6 - 10-3 moles of K 2 Cr 2 O 7 react completely with 9 - 10-3 moles of X n - to give XO 3-and Cr 3- The value of n is -A- 1B- 2C- 3D- None of these

The correct option is A 1When we write the oxidation and reduction nbsp;halves we find that Cr is getting reduced from +6 to +3 and since there are two Cr i ...

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Byju's Answer

Standard XII

Chemistry

Oxidising Reagent and Reducing Reagent

6 × 10-3 mole...

Question

$6 \times 10^{- 3}$ moles of $K_{2} C r_{2} O_{7}$ react completely with $9 \times 10^{- 3}$ moles of $X^{n +}$ to give $X O_{3}^{-}$ and $C r^{3 +}$ . The value of $n$ is :

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None of these

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Solution

The correct option is A 1
When we write the oxidation and reduction halves we find that
Cr is getting reduced from +6 to +3 and since there are two Cr ions so the n factor for Cr will be 6.
Similarly X will get oxidized from n to +5, so the n factor for X will be 5-n
We know that:
The number of equivalents of $K_{2} C r_{2} O_{7}$ = the number of equivalents of $X^{n +}$
So, moles of $K_{2} C r_{2} O_{7}$ × n factor of $K_{2} C r_{2} O_{7}$ = moles of $X^{n +}$ × n factor of $X^{n +}$
$6 \times 10^{- 3} \times 6 = 9 \times 10^{- 3} (5 - n)$
$4 = 5 - n$
$n = 1$

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Similar questions

6 \times 10^{- 3}

moles of

K_{2} C r_{2} O_{7}

reacts completely with

9 \times 10^{- 3}

moles of

X^{n +}

to give

X O_{3}^{-}

and

C r^{3 +}

. The value of n is:

6 \times 10^{- 3}

moles of

K_{2} C r_{2} O_{7}

react completely with

9 \times 10^{- 3}

moles of

X^{n +}

to give

X O_{3}^{-}

and

C r^{3 +}

. The value of

n

is :

6 \times 10^{- 3}

mole

K_{2} C r_{2} O_{7}

reacts completely with

9 \times 10^{- 3}

mole

X^{n +}

to give

X O_{3}^{-}

and

C r^{3 +}

. The value of

n

is:

6 \times 10^{- 3}

mole

K_{2} C r_{2} O_{7}

reacts completely with

9 \times 10^{- 3}

mole

X^{n +}

to give

X O_{3}^{-}

and

C r^{3 +}

. The value of 'n' is?

3 X 10^{- 3}

mole

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to give

X O_{3}^{-}

and

C r^{3 +}

. The value of n is :

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6×10−3 moles of K2Cr2O7 react completely with 9×10−3 moles of Xn+ to give XO−3 and Cr3+. The value of n is :

$6 \times 10^{- 3}$ moles of $K_{2} C r_{2} O_{7}$ react completely with $9 \times 10^{- 3}$ moles of $X^{n +}$ to give $X O_{3}^{-}$ and $C r^{3 +}$ . The value of $n$ is :