$6 x^{3} - 8 x^{2} + 4 x - 24$ by $2 x - 4$

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Solution

${6 x}^{3} - {8 x}^{2} + 4 x - 24$ by $2 x - 4$
$= 2 ({3 x}^{3} - {4 x}^{2} + 2 x - 12)$
$= 2 ({3 x}^{3} - {6 x}^{2} + {2 x}^{2} - 4 x + 6 x - 12)$
$= 2 [{3 x}^{2} (x - 2) + 2 x (x - 2) + 6 (x - 2)]$
$= 2 (x - 2) ({3 x}^{2} + 2 x + 6)$ by $2 x - 4$
$= \frac{2 (x - 2) ({3 x}^{2} + 2 x + 6)}{(2 x - 4)}$
$= {3 x}^{2} + 2 x + 6$

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6x3−8x2+4x−24 by 2x−4

6x3−8x2+4x−24 by 2x−4=2(3x3−4x2+2x−12)=2(3x3−6x2+2x2−4x+6x−12)=2[3x2(x−2)+2x(x−2)+6(x−2)]=2(x−2)(3x2+2x+6) by 2x−4=2(x−2)(3x2+2x+6)(2x−4)=3x2+2x+6

$6 x^{3} - 8 x^{2} + 4 x - 24$ by $2 x - 4$