Question

60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and alloy B has tin and copper in the ratio 1 : 4, then the amount of tin in the new alloy is

• A. 36 kg
• B. 44 kg
• C. 53 kg
• D. 80 kg

Answer 1

The correct option is B 44 kg

Alloy A has tin=$\frac{2}{5}\times 60=24Kg$
Alloy B has tin=$\frac{1}{5}\times 100=20Kg$
Then alloy C(A+B) has tin=$24+20=44Kg$