Question

$60kg$ of an alloy $X$ is mixed with $100$ kg of an alloy $Y$. If alloy $X$ has lead and tin in the ratio of $3:2$ and alloy $Y$ has tin and copper in the ratio of $1:4$, then the amount of tin in the new alloy is

• A. $53kgs.$
• B. $80kgs.$
• C. $44kgs.$
• D. $36kgs.$

Answer 1

Answer: (C)

$44kgs.$

Total amount of tin in alloy $x$ and $y$
$\frac{2x}{5}+\frac{1}{5}y$
$=\frac{2}{5}\times 60+\frac{1}{5}\times 100$
$=24+20=44kg$.