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Standard XIII

Chemistry

Stoichiometry

60 mL of mixt...

Question

60 mL of mixture of equal volumes of $C l_{2}$ and an oxide of chlorine, i.e., $C l_{2} O_{n}$ was heated and then cooled back to the original temperature, The resulting gas mixture was found to have volume of 75 mL. On treatment with KOH solution, the volume contracted to 15 mL. Assume that all measurements are made at the same temperature and pressure. Deduce the value of n in $C l_{2} O_{n}$ the oxide of $C l_{2}$ on heating decomposes quantitatively to $O_{2}$ and $C l_{2}$

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Solution

$\begin{matrix} C l_{2} + & C l_{2} O_{n} & \to & 2 C l_{2} + & \frac{n}{2} O_{2} 30 & 30 & 0 & 0 0 & 0 & 60 & 15 n \end{matrix}$
KOH absorbs $C l_{2}$
So, 15 n = 15
n = 1

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Cl2+Cl2On→2Cl2+n2O2303000006015n KOH absorbs Cl2 So, 15 n = 15 n = 1

$\begin{matrix} C l_{2} + & C l_{2} O_{n} & \to & 2 C l_{2} + & \frac{n}{2} O_{2} 30 & 30 & 0 & 0 0 & 0 & 60 & 15 n \end{matrix}$
KOH absorbs $C l_{2}$
So, 15 n = 15
n = 1