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Question

638.0 g of CuSO4 solution is titrated with excess of 0.2M KI solution. The liberated I2 required 400 mL of 1.0M Na2S2O3 for complete reaction. The percentage purity of CuSO4 in the sample is:

A
5%
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B
10%
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C
15%
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D
20%
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Solution

The correct option is D 10%
The overall reaction is as follows:
2Cu2++2eCu2
2II2+2e
________________________________________
2CuSO4+4KICu2I2+2K2SO4+I2
________________________________________
Reduction of I2 is given by, I2+2S2O232I+S4O24
2 mol CuSO44 mol KI1 mol I2 2 mol S2O23
milli moles CuSO4 milli moles S2O23 400×1 mmoles =0.4 mol
Weight of CuSO4=400×103×159.5 g
%CuSO4=400×103×159.5×100638=10%

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