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Acidic Nature vs Percentage S Characters

67.In Propano...

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67.In Propanone [ CH3 - CO -CH3] Oxygen atom has 2 lone pairs and 2 bond pairs then why is the hybridization sp2??

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Q. Find the ratio between

π

bonds and lone pairs of

s p^{2 -}

hybrid orbitals in

C_{3} N_{3} (N H_{2})_{3}

Assertion (A): Though the central atom of both

{N H}_{3}

H_{2} O

{s p}^{3} C

yet H-N-H bond angle is greater than that of H-O-H.

Reason (R): This is because nitrogen atom has a lone pair and oxygen atom has two lone pairs.

Q. Find the ratio of lone pairs present on

C l

s p^{2}

-hybrid orbital in

C_{3} N_{3} C l_{3}

Q. Which of the following species (A), (B), (C) and (D) has

s p^{2}

hybridized carbon?

C H {_{3}}^{+}

C H {_{3}}^{-}

∙ C H_{3}

C H_{2}

The species in which the central atom uses ${s p}^{2}$ - hybrid orbitals in its bonding is

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Acidic Nature vs Percentage S Characters

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