Question

$6a$ is a factor of the algebraic expression $36a+6\left(17a\right)$ because:

• A. $6a$ is the multiple of both the terms.
  
• B. $6a$ divides only the first term of the expression and is not a factor of the second term.
  
• C. $6a$ is not the coefficient of both the terms.
  
• D. $6a$ is the factor of both the terms and divides each term completely.
  

Answer 1

The correct option is D $6a$ is the factor of both the terms and divides each term completely.


In the expression $36a+6\times 17a$,
first term $=36a$
second term $=6\times 17a=102a$
Dividing $36a$ with $6a=36a÷6a=6$
Dividing $102a$ with $6a=102a÷6a=17$
So, it means that $6a$ is the factor of expression as it divides both terms.
Hence, option D is correct.