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Question

Factorize each of the following algebraic expressions:
6(a + 2b) −4(a + 2b)2

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Solution

6(a+2b)-4(a+2b)2=[6-4(a+2b)](a+2b) [Taking (a+2b) as the common factor]= 2[3-2(a+2b)](a+2b) {Taking 2 as the common factor of [6-4(a+2b)]}=2(3-2a-4b)(a+2b)

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