Factorize the following algebraic expressions: 7a(2x−3)+3b(2x−3)
Given: 7a(2x−3)+3b(2x−3)
Taking (2x−3) common, we get,
=(2x−3)(7a+3b)
Hence, 7a(2x−3)+3b(2x−3)=(2x−3)(7a+3b)