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Question

Factorize the following algebraic expressions: 7a(2x3)+3b(2x3)

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Solution

Given: 7a(2x3)+3b(2x3)

Taking (2x3) common, we get,

=(2x3)(7a+3b)

Hence, 7a(2x3)+3b(2x3)=(2x3)(7a+3b)


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