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Question

Factorize each of the following algebraic expressions:
16(2l − 3m)2 −12(3m − 2l)

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Solution

16(2l-3m)2-12(3m-2l)=16(2l-3m)2+12(2l-3m) [(3m-2l)=-(2l-3m)]= [16(2l-3m)+12](2l-3m) [Taking (2l-3m) as the common factor]=4[4(2l-3m)+3](2l-3m) {Taking 4 as the common factor of [16(2l-3m)+12]}=4(8l-12m+3)(2l-3m)

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