Question

$6x^2+11x+3=0$

Answer 1

$$\begin{gathered} \mathrm{Given}: \\ \text{6}{x}^2+11x+3=0 \\ \Rightarrow 6x^2+9x+2x+3=0 \\ \Rightarrow 3x(2x+3)+1(2x+3)=0 \\ \Rightarrow (3x+1)(2x+3)=0 \\ \Rightarrow 3x+1=0\text{or}2x+3=0 \\ \Rightarrow x=\frac{-1}{3}\text{or}x=\frac{-3}{2} \\ \text{Hence,}\frac{-1}{3}\text{and}\frac{-3}{2}\text{are the roots of the equation 6}{x}^2+11x+3=0. \end{gathered}$$