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Byju's Answer
Standard XII
Mathematics
Sequence
7, 13, 19,......
Question
7
,
13
,
19
,
.
.
.
.
,
205
.
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Solution
The given series is
7
,
13
,
19
,
.
.
.
,
205
The given series is in
A
P
Here
a
=
7
,
d
=
6
So the general term is
a
n
=
a
+
(
n
−
1
)
d
a
n
=
7
+
(
n
−
1
)
6
6
n
+
1
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3
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.
.
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Question 5 (i)
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(i)
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