$_{7}^{14} N$ is attacked by doubly charged helium ion, it emits a proton and:

_{9}^{18} F

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_{8}^{17} O

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_{8}^{18} O

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_{9}^{19} F

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Solution

The correct option is B $_{8}^{17} O$
If Nitrogen is attacked by doubly charged helium ion, it emits proton and $_{8} O^{17}$ .

$_{7}^{14} N +_{2}^{4} H e ⟶$ $_{8}^{17} O +_{1}^{1} H$

Hence, option B is correct.

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