The given function is e 6x cos3x.
Let y= e 6x cos3x.
Differentiate function y with respect to x.
dy dx = d( e 6x cos3x ) dx dy dx = d( e 6x ) dx .cos3x+ d( cos3x ) dx . e 6x dy dx =6 e 6x ( cos3x )−sin3x( 3 e 6x ) dy dx =3 e 6x ( 2cos3x−sin3x )
Again, differentiate with respect to x.
d dx ( dy dx )= d( 3 e 6x ( 2cos3x−sin3x ) ) dx d 2 y d x 2 =3( d( e 6x ) dx ( 2cos3x−sin3x )+ d( 2cos3x−sin3x ) dx . e 6x ) d 2 y d x 2 =3( 6 e 6x ( 2cos3x−sin3x )−3( 2sin3x+cos3x ). e 6x ) d 2 y d x 2 =3( 12 e 6x cos3x−6 e 6x sin3x−6 e 6x sin3x−3 e 6x cos3x )
Simplify further,
d 2 y d x 2 =3( 9 e 6x cos3x−12 e 6x sin3x ) d 2 y d x 2 =9 e 6x ( 3cos3x−4sin3x )
Thus, the second order derivative of the given function is 9 e 6x ( 3cos3x−4sin3x ).