7.Explain the comparison of oxidative property of Sn4+ and Sn2+ ions on the basis of inert pair effect

Open in App

Solution

Suggest Corrections

Similar questions

Q. The correct code for stability of oxidation states of Sn and Pb is :

[1] P b^{2 +} > P b^{4}, S n^{2 +} > S n^{4 +}

[2] P b^{2 +} < P b^{4}, S n^{2 +} < S n^{4 +}

[3] P b^{2 +} > P b^{4}, S n^{2 +} < S n^{4 +}

[4] P b^{2 +} < P b^{4}, S n^{2 +} > S n^{4 +}

[5] S n^{2 +} < P b^{2 +}, S n^{4 +} > P b^{4 +}

[6] S n^{2 +} < P b^{2 +}, S n^{4 +} < P b^{4 +}

Stability of ions of $G e, S n, a n d P b$ will be in the order:

When the ion ${C r}_{2} O_{7}^{2 -}$ acts as an oxidant in acidic aqueous solution the ion ${C r}^{3 +}$ is formed. How many moles of ${S n}^{2 +}$ would be oxidised to ${S n}^{4 +}$ by one mole of ${C r}_{2} O_{7}^{2 -}$ ions?

Distinguish between metals and non-metals on the basis of:

(i) ion information, (ii) discharge of ions, (iii) nature of oxide formed, (iv) oxidising and reducing property, (v) reaction with acids.

Q. When the ion

C r_{2} O_{7}^{- 2}

acts as an oxidant in acidic aqueous solution the ion

C r^{3 +}

is formed. How many mole of

S n^{2} +

would be oxidized to

S n^{4 +}

by 2/3 moles of

C r_{2} O_{7}^{- 2}

ions?

Join BYJU'S Learning Program