71. 1.5 moles of $C l O_{2}$ reacts with 72g of $O_{3}$ according to reaction
$2 C l O_{2} + 2 O_{3} ⟶ {C l}_{2} O_{6} + 2 O_{2}$ .0.6 moles of Cl2O6 is formed .What is the % yield of reaction?

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C l_{2} O_{6}

\frac{1}{2}

A l_{2} O_{3}

2 A l + \frac{3}{2} O_{2} ⟶ {A l}_{2} O_{3}

A (g) + B (g) ⇌ C (g) + D (g)

4

A

4

B

2

C

C l_{2} O_{6}

10

H C l

0.3

C a C O_{3} (s) + 2 H C l (a q) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)

C a C l_{2}

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71. 1.5 moles of ClO2 reacts with 72g of O3 according to reaction 2ClO2+2O3⟶Cl2O6+2O2 .0.6 moles of Cl2O6 is formed .What is the % yield of reaction?