Question

74.5 g of a metallic chloride contain 35.5 g of chlorine. The equivalent weight of the metal is

• A. 19.5
• B. 35.5
• C. 39
• D. 78

Answer 1

The correct option is C 39

wt. of metallic chloride =74.5
wt. of chlorine = 35.5
$\therefore$ wt. of metal =74.5-35.5=39
Equivalent weight of metal $=\frac{weightofmetal}{weightofchlorine}\times 35.5$
$=\frac{39}{35.5}\times 35.5=39$