The correct option is D 1 cm
Volume of the metallic cylindrical pipe=748cc=748cm3
Length of the cylindrical pipe, h=14cm
External radius of the pipe,R=9cm
Let the internal radius of the cylindrical pipe be ′r′cm
Therefore the volume of the metallic pipe=π(R2−r2)h
⇒227(92−r2)×14=748⇒44(81−r2)=748
⇒81−r2=74844=17⇒r2=81−17=64
⇒r=√64=8cm
Therefore, thickness of metallic pipe=R−r=9−8=1cm