-8 -3- -4- is not equal to

The correct option is D ( 8) × ( 3) ( 8) × ( 4) [( 8) × ( 3)] × ( 4) = [( 3) × ( 8)] × ( 4) =( 3) × [( 8) × ( 4)] [ ∵ a × (b × c) = (a × b) × c] = [( 8 ...

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Byju's Answer

Standard VIII

Mathematics

Multiplication of Negative Numbers

[-8 ×-3] ×-4]...

Question

$[(- 8) \times (- 3)] \times (- 4)]$ is not equal to

$(- 8) \times [(- 3) \times (- 4)]$

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$[(- 8) \times (- 4)] \times (- 3)$

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$[(- 3) \times (- 8)] \times (- 4)$

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$(- 8) \times (- 3) - (- 8) \times (- 4)$

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Solution

The correct option is D
$(- 8) \times (- 3) - (- 8) \times (- 4)$

$[(- 8) \times (- 3)] \times (- 4) = [(- 3) \times (- 8)] \times (- 4)$

= $(- 3) \times [(- 8) \times (- 4)]$ $[∵$ $a \times (b \times c) = (a \times b) \times c]$
$= [(- 8) \times (- 4)] \times (- 3)$
$= (- 8) \times [(- 4) \times (- 3)]$
$\neq (- 8) \times (- 3) - (- 8) \times (- 4)$
Hence, $[- (8) \times (- 3)] \times (- 4)$ is not equal to $(- 8) \times (- 3) - (- 8) \times (- 4) .$

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Similar questions

$[(- 8) \times (- 3)] \times (- 4)]$ is not equal to

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(b) $[(- 8) \times (- 4)] \times (- 3)$
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