Question

${}_{84}^{218}Po(t_{1/2}=183sec)$ decays to ${}_{82}^{214}Pb(t_{1/2}=161sec)$ by $\alpha -$emission, while ${}_{82}^{214}Pb$ decays by $\beta -$emission.

In how much time the number of nuclei of ${}_{82}^{214}Pb$ will reach to the maximum?

• A. $182$ $sec$
• B. $247.5$ $sec$
• C. $308$ $sec$
• D. $194.8$ $sec$

Answer 1

The correct option is B $247.5$ $sec$